In today’s free math problem solver session we are going to discuss how to solve percent problems in mathematics. This is the very important part of mathematics. Most of the problems are based on the percentage. Here we will discuss about such problems related to Grade IV.
We generally face percents problems which are chiefly of three types: (for more detail read this)
1. Missing Percent Problems: In such problems the task is to find what percent one quantity is of the other quantity.
2. Missing Part Problem: In this kind of problems we need to find what quantity is given percent of other quantity.
3. Missing Whole Problem: In this kind of problems we find the full or whole quantity given what percent a certain quantity is, like the 100%.
In the above mentioned problems the 3rd problem is difficult.
If we need to find 15% of 150, we generally first convert the 15% to its compatible decimal form i.e. 0.15. Now 15% of 150 indicate us to multiply the 0.15 and 150, and then we will get 0.15*150 = 22.5. That means 22.5 is the 15th percent of the 150.
Now here is some examples related to the percents problems:
a. What percent of 20 is 25%?
We first have the original number 20 with the comparative number 25. Now we need to find the rate or the percentage. So let the percentage be x.
25 = x * 20
25/20 = x
x = 1.25
Now the task is to convert this decimal back into the percentage: 1.25 = 125%
Now we can say that 25 is the 125% of 20.
b. What is 35% of 50?
X = 0.35 * 50 (here x stands for a number)
X = 17.5
Now the 17.5 is 35% of 50.
So today we learnt about the percents problem.
In upcoming posts we will discuss about Addition and subtraction and Powers and repeated multiplication in Grade V. Visit our website for information on CBSE political science board paper
We generally face percents problems which are chiefly of three types: (for more detail read this)
1. Missing Percent Problems: In such problems the task is to find what percent one quantity is of the other quantity.
2. Missing Part Problem: In this kind of problems we need to find what quantity is given percent of other quantity.
3. Missing Whole Problem: In this kind of problems we find the full or whole quantity given what percent a certain quantity is, like the 100%.
In the above mentioned problems the 3rd problem is difficult.
If we need to find 15% of 150, we generally first convert the 15% to its compatible decimal form i.e. 0.15. Now 15% of 150 indicate us to multiply the 0.15 and 150, and then we will get 0.15*150 = 22.5. That means 22.5 is the 15th percent of the 150.
Now here is some examples related to the percents problems:
a. What percent of 20 is 25%?
We first have the original number 20 with the comparative number 25. Now we need to find the rate or the percentage. So let the percentage be x.
25 = x * 20
25/20 = x
x = 1.25
Now the task is to convert this decimal back into the percentage: 1.25 = 125%
Now we can say that 25 is the 125% of 20.
b. What is 35% of 50?
X = 0.35 * 50 (here x stands for a number)
X = 17.5
Now the 17.5 is 35% of 50.
So today we learnt about the percents problem.
In upcoming posts we will discuss about Addition and subtraction and Powers and repeated multiplication in Grade V. Visit our website for information on CBSE political science board paper
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