This unit is designed for Grade IV and here in help in math session we are going to learn about Multiplication problems. We know that multiplication word means to add repeatedly and to increase in the fixed quantity. Here we are dealing with the problems of multiplication, we need to first learn that what all are the problems of multiplication, how to do double digit multiplication and how to recognize such problems.
Some times we come across real life problems, in which we are given the cost of one article and we need to find the cost of more than one article. For instance if we say that the cost of 1 cod drink is $2, now if a child wants to buy 2 cold drinks, he needs $2 + $ 2 =$4 . Further if he requires three cold drinks, he will spend $2 + $ 2 + $2 = $ 6. Thus what we observe is that every time the number of cold drinks is increasing , we are adding $2 to the previous total, or we can say that the cost of unit article is added the number of times the object is required. It can also be done more easily if there are n number of objects and the cost of 1 article is multiplied by n. for more on this subject visit this
This is easier and simple method of getting the solution for problems of multiplication.
Example: If 1 sack of rice cost 25$, then find the cost of 5 sacks of cement.
Sol: We know that the cost of 1 sack of cement = $ 25
So, to find the cost of 5 sacks of cement, we need to multiply the cost of the unit sack by the number of the sacks required.
So we get = $25 * 5 = 125 $
In this way all such real life problems can be solved using multiplication.
In upcoming posts we will discuss about Factors and products and Measurement in Grade V. Visit our website for information on 12th biology Maharashtra board syllabus
Some times we come across real life problems, in which we are given the cost of one article and we need to find the cost of more than one article. For instance if we say that the cost of 1 cod drink is $2, now if a child wants to buy 2 cold drinks, he needs $2 + $ 2 =$4 . Further if he requires three cold drinks, he will spend $2 + $ 2 + $2 = $ 6. Thus what we observe is that every time the number of cold drinks is increasing , we are adding $2 to the previous total, or we can say that the cost of unit article is added the number of times the object is required. It can also be done more easily if there are n number of objects and the cost of 1 article is multiplied by n. for more on this subject visit this
This is easier and simple method of getting the solution for problems of multiplication.
Example: If 1 sack of rice cost 25$, then find the cost of 5 sacks of cement.
Sol: We know that the cost of 1 sack of cement = $ 25
So, to find the cost of 5 sacks of cement, we need to multiply the cost of the unit sack by the number of the sacks required.
So we get = $25 * 5 = 125 $
In this way all such real life problems can be solved using multiplication.
In upcoming posts we will discuss about Factors and products and Measurement in Grade V. Visit our website for information on 12th biology Maharashtra board syllabus
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